Base | Representation |
---|---|
bin | 100100101101110101100… |
… | …010101101111100111001 |
3 | 22221012121102100102022220 |
4 | 210231311202231330321 |
5 | 312314321131310022 |
6 | 5211034311434253 |
7 | 350201132522421 |
oct | 44556542557471 |
9 | 8835542312286 |
10 | 2523117838137 |
11 | 893059273236 |
12 | 348bb7085989 |
13 | 153c0ccbc1c0 |
14 | 8a1960b7481 |
15 | 4597344a85c |
hex | 24b758adf39 |
2523117838137 has 64 divisors (see below), whose sum is σ = 3852314484480. Its totient is φ = 1455170863104.
The previous prime is 2523117838121. The next prime is 2523117838169. The reversal of 2523117838137 is 7318387113252.
It is not a de Polignac number, because 2523117838137 - 24 = 2523117838121 is a prime.
It is a super-2 number, since 2×25231178381372 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 2523117838137.
It is not an unprimeable number, because it can be changed into a prime (2523117838117) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 164076193 + ... + 164091569.
It is an arithmetic number, because the mean of its divisors is an integer number (60192413820).
Almost surely, 22523117838137 is an apocalyptic number.
It is an amenable number.
2523117838137 is a deficient number, since it is larger than the sum of its proper divisors (1329196646343).
2523117838137 is a wasteful number, since it uses less digits than its factorization.
2523117838137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16442.
The product of its digits is 1693440, while the sum is 51.
The spelling of 2523117838137 in words is "two trillion, five hundred twenty-three billion, one hundred seventeen million, eight hundred thirty-eight thousand, one hundred thirty-seven".
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