Search a number
-
+
252315005511 = 384105001837
BaseRepresentation
bin1110101011111100100…
…1010111001001000111
3220010021021012022200010
43222333021113021013
513113220120134021
6311524550121303
724141413105652
oct3527711271107
9803237168603
10252315005511
1198008274148
1240a97950233
131aa4088903a
14c2d8068899
15686b1a1976
hex3abf257247

252315005511 has 4 divisors (see below), whose sum is σ = 336420007352. Its totient is φ = 168210003672.

The previous prime is 252315005473. The next prime is 252315005519. The reversal of 252315005511 is 115500513252.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 252315005511 - 221 = 252312908359 is a prime.

It is a super-2 number, since 2×2523150055112 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252315005519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42052500916 + ... + 42052500921.

It is an arithmetic number, because the mean of its divisors is an integer number (84105001838).

Almost surely, 2252315005511 is an apocalyptic number.

252315005511 is a deficient number, since it is larger than the sum of its proper divisors (84105001841).

252315005511 is an equidigital number, since it uses as much as digits as its factorization.

252315005511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84105001840.

The product of its (nonzero) digits is 7500, while the sum is 30.

Adding to 252315005511 its reverse (115500513252), we get a palindrome (367815518763).

The spelling of 252315005511 in words is "two hundred fifty-two billion, three hundred fifteen million, five thousand, five hundred eleven".

Divisors: 1 3 84105001837 252315005511