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25243157437 is a prime number
BaseRepresentation
bin10111100000100111…
…000000001110111101
32102011020110021002221
4113200213000032331
5403144222014222
615332504245341
71552356204121
oct274047001675
972136407087
1025243157437
11a784116893
124a85a70851
1324c3a21564
1413167a1581
159cb2040c7
hex5e09c03bd

25243157437 has 2 divisors, whose sum is σ = 25243157438. Its totient is φ = 25243157436.

The previous prime is 25243157419. The next prime is 25243157449. The reversal of 25243157437 is 73475134252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24946938916 + 296218521 = 157946^2 + 17211^2 .

It is a cyclic number.

It is not a de Polignac number, because 25243157437 - 223 = 25234768829 is a prime.

It is a super-3 number, since 3×252431574373 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25243157393 and 25243157402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25243152437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12621578718 + 12621578719.

It is an arithmetic number, because the mean of its divisors is an integer number (12621578719).

Almost surely, 225243157437 is an apocalyptic number.

It is an amenable number.

25243157437 is a deficient number, since it is larger than the sum of its proper divisors (1).

25243157437 is an equidigital number, since it uses as much as digits as its factorization.

25243157437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 705600, while the sum is 43.

The spelling of 25243157437 in words is "twenty-five billion, two hundred forty-three million, one hundred fifty-seven thousand, four hundred thirty-seven".