2525277780253 has 4 divisors (see below), whose sum is σ = 2551311571900. Its totient is φ = 2499243988608.

The previous prime is 2525277780247. The next prime is 2525277780257. The reversal of 2525277780253 is 3520877725252.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1762593451129 + 762684329124 = 1327627^2 + 873318^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2525277780253 is a prime.

It is a super-3 number, since 3×2525277780253³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2525277780194 and 2525277780203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2525277780257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13016895678 + ... + 13016895871.

It is an arithmetic number, because the mean of its divisors is an integer number (637827892975).

Almost surely, 2^{2525277780253} is an apocalyptic number.

It is an amenable number.

2525277780253 is a deficient number, since it is larger than the sum of its proper divisors (26033791647).

2525277780253 is an equidigital number, since it uses as much as digits as its factorization.

2525277780253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26033791646.

The product of its (nonzero) digits is 16464000, while the sum is 55.

The spelling of 2525277780253 in words is "two trillion, five hundred twenty-five billion, two hundred seventy-seven million, seven hundred eighty thousand, two hundred fifty-three".