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252543221237 is a prime number
BaseRepresentation
bin1110101100110010111…
…1111011110111110101
3220010212011121212210102
43223030233323313311
513114202031034422
6312003341403445
724150153650636
oct3531457736765
9803764555712
10252543221237
1198115078a8a
1240b40269585
131aa78c42128
14c31a4b388d
156881231192
hex3accbfbdf5

252543221237 has 2 divisors, whose sum is σ = 252543221238. Its totient is φ = 252543221236.

The previous prime is 252543221197. The next prime is 252543221239. The reversal of 252543221237 is 732122345252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174478302436 + 78064918801 = 417706^2 + 279401^2 .

It is a cyclic number.

It is not a de Polignac number, because 252543221237 - 210 = 252543220213 is a prime.

Together with 252543221239, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 252543221237.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (252543221239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126271610618 + 126271610619.

It is an arithmetic number, because the mean of its divisors is an integer number (126271610619).

Almost surely, 2252543221237 is an apocalyptic number.

It is an amenable number.

252543221237 is a deficient number, since it is larger than the sum of its proper divisors (1).

252543221237 is an equidigital number, since it uses as much as digits as its factorization.

252543221237 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 201600, while the sum is 38.

Adding to 252543221237 its reverse (732122345252), we get a palindrome (984665566489).

The spelling of 252543221237 in words is "two hundred fifty-two billion, five hundred forty-three million, two hundred twenty-one thousand, two hundred thirty-seven".