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25284384507967 = 131944952654459
BaseRepresentation
bin1011011111110111110101…
…10000011100100000111111
310022112011102020012110210021
411233323322300130200333
511303224404413223332
6125435252541353011
75216510422145524
oct557737260344077
9108464366173707
1025284384507967
11806905798a582
122a04349268767
1311153cbc99690
14635ab0ca514b
152dca88dc3c97
hex16fefac1c83f

25284384507967 has 4 divisors (see below), whose sum is σ = 27229337162440. Its totient is φ = 23339431853496.

The previous prime is 25284384507919. The next prime is 25284384508001. The reversal of 25284384507967 is 76970548348252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25284384507967 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25284384507896 and 25284384507905.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25284384607967) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 972476327217 + ... + 972476327242.

It is an arithmetic number, because the mean of its divisors is an integer number (6807334290610).

Almost surely, 225284384507967 is an apocalyptic number.

25284384507967 is a deficient number, since it is larger than the sum of its proper divisors (1944952654473).

25284384507967 is a wasteful number, since it uses less digits than its factorization.

25284384507967 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1944952654472.

The product of its (nonzero) digits is 812851200, while the sum is 70.

The spelling of 25284384507967 in words is "twenty-five trillion, two hundred eighty-four billion, three hundred eighty-four million, five hundred seven thousand, nine hundred sixty-seven".

Divisors: 1 13 1944952654459 25284384507967