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2530011311117 is a prime number
BaseRepresentation
bin100100110100010000011…
…011001110110000001101
322221212101211122010111222
4210310100123032300031
5312422430343423432
65214134322453125
7350534016213323
oct44642033166015
98855354563458
102530011311117
11895a76478544
1234a3bb8041a5
1315476b2077b4
148a64b823d13
1545c28721112
hex24d106cec0d

2530011311117 has 2 divisors, whose sum is σ = 2530011311118. Its totient is φ = 2530011311116.

The previous prime is 2530011311099. The next prime is 2530011311309. The reversal of 2530011311117 is 7111131100352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2100821235241 + 429190075876 = 1449421^2 + 655126^2 .

It is a cyclic number.

It is not a de Polignac number, because 2530011311117 - 26 = 2530011311053 is a prime.

It is a super-2 number, since 2×25300113111172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2530011311417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265005655558 + 1265005655559.

It is an arithmetic number, because the mean of its divisors is an integer number (1265005655559).

Almost surely, 22530011311117 is an apocalyptic number.

It is an amenable number.

2530011311117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530011311117 is an equidigital number, since it uses as much as digits as its factorization.

2530011311117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 26.

Adding to 2530011311117 its reverse (7111131100352), we get a palindrome (9641142411469).

The spelling of 2530011311117 in words is "two trillion, five hundred thirty billion, eleven million, three hundred eleven thousand, one hundred seventeen".