Base | Representation |
---|---|
bin | 100100110100010000011… |
… | …011001110110011001101 |
3 | 22221212101211122010210002 |
4 | 210310100123032303031 |
5 | 312422430343430214 |
6 | 5214134322454045 |
7 | 350534016214016 |
oct | 44642033166315 |
9 | 8855354563702 |
10 | 2530011311309 |
11 | 895a764786a9 |
12 | 34a3bb804325 |
13 | 15476b207901 |
14 | 8a64b82400d |
15 | 45c287211de |
hex | 24d106ceccd |
2530011311309 has 2 divisors, whose sum is σ = 2530011311310. Its totient is φ = 2530011311308.
The previous prime is 2530011311117. The next prime is 2530011311369. The reversal of 2530011311309 is 9031131100352.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2334545638084 + 195465673225 = 1527922^2 + 442115^2 .
It is a cyclic number.
It is not a de Polignac number, because 2530011311309 - 28 = 2530011311053 is a prime.
It is a super-3 number, since 3×25300113113093 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2530011311369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265005655654 + 1265005655655.
It is an arithmetic number, because the mean of its divisors is an integer number (1265005655655).
Almost surely, 22530011311309 is an apocalyptic number.
It is an amenable number.
2530011311309 is a deficient number, since it is larger than the sum of its proper divisors (1).
2530011311309 is an equidigital number, since it uses as much as digits as its factorization.
2530011311309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2430, while the sum is 29.
The spelling of 2530011311309 in words is "two trillion, five hundred thirty billion, eleven million, three hundred eleven thousand, three hundred nine".
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