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2530011311309 is a prime number
BaseRepresentation
bin100100110100010000011…
…011001110110011001101
322221212101211122010210002
4210310100123032303031
5312422430343430214
65214134322454045
7350534016214016
oct44642033166315
98855354563702
102530011311309
11895a764786a9
1234a3bb804325
1315476b207901
148a64b82400d
1545c287211de
hex24d106ceccd

2530011311309 has 2 divisors, whose sum is σ = 2530011311310. Its totient is φ = 2530011311308.

The previous prime is 2530011311117. The next prime is 2530011311369. The reversal of 2530011311309 is 9031131100352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2334545638084 + 195465673225 = 1527922^2 + 442115^2 .

It is a cyclic number.

It is not a de Polignac number, because 2530011311309 - 28 = 2530011311053 is a prime.

It is a super-3 number, since 3×25300113113093 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2530011311369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265005655654 + 1265005655655.

It is an arithmetic number, because the mean of its divisors is an integer number (1265005655655).

Almost surely, 22530011311309 is an apocalyptic number.

It is an amenable number.

2530011311309 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530011311309 is an equidigital number, since it uses as much as digits as its factorization.

2530011311309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2430, while the sum is 29.

The spelling of 2530011311309 in words is "two trillion, five hundred thirty billion, eleven million, three hundred eleven thousand, three hundred nine".