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2530052801207 is a prime number
BaseRepresentation
bin100100110100010010111…
…001100000001010110111
322221212111201201001012222
4210310102321200022313
5312423022004114312
65214142404032555
7350535031655561
oct44642271401267
98855451631188
102530052801207
11895a97936678
1234a41169275b
131547769a3649
148a653144331
1545c2c1b9672
hex24d12e602b7

2530052801207 has 2 divisors, whose sum is σ = 2530052801208. Its totient is φ = 2530052801206.

The previous prime is 2530052801197. The next prime is 2530052801209. The reversal of 2530052801207 is 7021082500352.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2530052801207 - 234 = 2512872932023 is a prime.

Together with 2530052801209, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2530052801209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265026400603 + 1265026400604.

It is an arithmetic number, because the mean of its divisors is an integer number (1265026400604).

Almost surely, 22530052801207 is an apocalyptic number.

2530052801207 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530052801207 is an equidigital number, since it uses as much as digits as its factorization.

2530052801207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 35.

The spelling of 2530052801207 in words is "two trillion, five hundred thirty billion, fifty-two million, eight hundred one thousand, two hundred seven".