Base | Representation |
---|---|
bin | 1011100000010110101011… |
… | …00011001010110101100000 |
3 | 10022120202011000112201021022 |
4 | 11300023111203022311200 |
5 | 11304012311133433442 |
6 | 125451031430145012 |
7 | 5220634611535115 |
oct | 560132543126540 |
9 | 108522130481238 |
10 | 25300940139872 |
11 | 80750831298a1 |
12 | 2a075a97b2168 |
13 | 1116b39bb5687 |
14 | 63680195090c |
15 | 2dd2075713d2 |
hex | 1702d58cad60 |
25300940139872 has 12 divisors (see below), whose sum is σ = 49811225900436. Its totient is φ = 12650470069920.
The previous prime is 25300940139857. The next prime is 25300940139877. The reversal of 25300940139872 is 27893104900352.
It is a super-4 number, since 4×253009401398724 (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25300940139877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 395327189654 + ... + 395327189717.
It is an arithmetic number, because the mean of its divisors is an integer number (4150935491703).
Almost surely, 225300940139872 is an apocalyptic number.
It is an amenable number.
25300940139872 is a deficient number, since it is larger than the sum of its proper divisors (24510285760564).
25300940139872 is an equidigital number, since it uses as much as digits as its factorization.
25300940139872 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 790654379381 (or 790654379373 counting only the distinct ones).
The product of its (nonzero) digits is 3265920, while the sum is 53.
The spelling of 25300940139872 in words is "twenty-five trillion, three hundred billion, nine hundred forty million, one hundred thirty-nine thousand, eight hundred seventy-two".
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