253011401 has 2 divisors, whose sum is σ = 253011402. Its totient is φ = 253011400.

The previous prime is 253011383. The next prime is 253011419. The reversal of 253011401 is 104110352.

253011401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (253011383) and next prime (253011419).

It can be written as a sum of positive squares in only one way, i.e., 228765625 + 24245776 = 15125^2 + 4924^2 .

It is a cyclic number.

It is not a de Polignac number, because 253011401 - 2²² = 248817097 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 253011401.

It is not a weakly prime, because it can be changed into another prime (253011461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126505700 + 126505701.

It is an arithmetic number, because the mean of its divisors is an integer number (126505701).

Almost surely, 2^253011401 is an apocalyptic number.

It is an amenable number.

253011401 is a deficient number, since it is larger than the sum of its proper divisors (1).

253011401 is an equidigital number, since it uses as much as digits as its factorization.

253011401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 253011401 is about 15906.3321039138. The cubic root of 253011401 is about 632.4798545871.

Adding to 253011401 its reverse (104110352), we get a palindrome (357121753).

It can be divided in two parts, 2530 and 11401, that added together give a palindrome (13931).

The spelling of 253011401 in words is "two hundred fifty-three million, eleven thousand, four hundred one".