Base | Representation |
---|---|
bin | 10111100100111010… |
… | …100101100111000111 |
3 | 2102100021101120110102 |
4 | 113210322211213013 |
5 | 403321220301020 |
6 | 15344004514315 |
7 | 1554224231204 |
oct | 274472454707 |
9 | 72307346412 |
10 | 25315400135 |
11 | a8109798a3 |
12 | 4aa60ab99b |
13 | 2505996b0c |
14 | 1322208cab |
15 | 9d2724475 |
hex | 5e4ea59c7 |
25315400135 has 4 divisors (see below), whose sum is σ = 30378480168. Its totient is φ = 20252320104.
The previous prime is 25315400113. The next prime is 25315400197. The reversal of 25315400135 is 53100451352.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25315400135 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25315400098 and 25315400107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2531540009 + ... + 2531540018.
It is an arithmetic number, because the mean of its divisors is an integer number (7594620042).
Almost surely, 225315400135 is an apocalyptic number.
25315400135 is a deficient number, since it is larger than the sum of its proper divisors (5063080033).
25315400135 is an equidigital number, since it uses as much as digits as its factorization.
25315400135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5063080032.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 25315400135 its reverse (53100451352), we get a palindrome (78415851487).
The spelling of 25315400135 in words is "twenty-five billion, three hundred fifteen million, four hundred thousand, one hundred thirty-five".
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