253160113283113 has 4 divisors (see below), whose sum is σ = 253167238367568. Its totient is φ = 253152988198660.

The previous prime is 253160113283111. The next prime is 253160113283137. The reversal of 253160113283113 is 311382311061352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 253160113283113 - 2¹ = 253160113283111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (253160113283111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3562488931 + ... + 3562559992.

It is an arithmetic number, because the mean of its divisors is an integer number (63291809591892).

Almost surely, 2^{253160113283113} is an apocalyptic number.

It is an amenable number.

253160113283113 is a deficient number, since it is larger than the sum of its proper divisors (7125084455).

253160113283113 is an equidigital number, since it uses as much as digits as its factorization.

253160113283113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7125084454.

The product of its (nonzero) digits is 77760, while the sum is 40.

The spelling of 253160113283113 in words is "two hundred fifty-three trillion, one hundred sixty billion, one hundred thirteen million, two hundred eighty-three thousand, one hundred thirteen".