Base | Representation |
---|---|
bin | 111001100011111101101110… |
… | …100111111010000000101010 |
3 | 1020012100212111120110010101012 |
4 | 321203331232213322000222 |
5 | 231140233403000024424 |
6 | 2254232052301423522 |
7 | 104216133415533512 |
oct | 7143755647720052 |
9 | 1205325446403335 |
10 | 253160113283114 |
11 | 73734668094584 |
12 | 2448816186aba2 |
13 | ab34b8609319b |
14 | 467302cac6842 |
15 | 1e4041ed0ab0e |
hex | e63f6e9fa02a |
253160113283114 has 8 divisors (see below), whose sum is σ = 380015144707908. Its totient is φ = 126488398380480.
The previous prime is 253160113283111. The next prime is 253160113283137. The reversal of 253160113283114 is 411382311061352.
It can be written as a sum of positive squares in 2 ways, for example, as 224376941933089 + 28783171350025 = 14979217^2 + 5364995^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×2531601132831142 (a number of 30 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (253160113283111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45829127087 + ... + 45829132610.
Almost surely, 2253160113283114 is an apocalyptic number.
253160113283114 is a deficient number, since it is larger than the sum of its proper divisors (126855031424794).
253160113283114 is a wasteful number, since it uses less digits than its factorization.
253160113283114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91658261080.
The product of its (nonzero) digits is 103680, while the sum is 41.
The spelling of 253160113283114 in words is "two hundred fifty-three trillion, one hundred sixty billion, one hundred thirteen million, two hundred eighty-three thousand, one hundred fourteen".
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