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253241251997 is a prime number
BaseRepresentation
bin1110101111011001011…
…0101101100010011101
3220012122211002111222112
43223312112231202131
513122114230030442
6312200514523405
724203361061016
oct3536626554235
9805584074875
10253241251997
11984430a2908
12410b5b96565
131ab5a742096
14c38509800d
1568c2665082
hex3af65ad89d

253241251997 has 2 divisors, whose sum is σ = 253241251998. Its totient is φ = 253241251996.

The previous prime is 253241251979. The next prime is 253241252003. The reversal of 253241251997 is 799152142352.

Together with previous prime (253241251979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 248935136356 + 4306115641 = 498934^2 + 65621^2 .

It is a cyclic number.

It is not a de Polignac number, because 253241251997 - 228 = 252972816541 is a prime.

It is a super-2 number, since 2×2532412519972 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253241251097) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126620625998 + 126620625999.

It is an arithmetic number, because the mean of its divisors is an integer number (126620625999).

Almost surely, 2253241251997 is an apocalyptic number.

It is an amenable number.

253241251997 is a deficient number, since it is larger than the sum of its proper divisors (1).

253241251997 is an equidigital number, since it uses as much as digits as its factorization.

253241251997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1360800, while the sum is 50.

The spelling of 253241251997 in words is "two hundred fifty-three billion, two hundred forty-one million, two hundred fifty-one thousand, nine hundred ninety-seven".