Base | Representation |
---|---|
bin | 111001100110001010101000… |
… | …000000111011110000000011 |
3 | 1020012220100000000002122200210 |
4 | 321212022220000323300003 |
5 | 231200223221400004030 |
6 | 2254425352313045203 |
7 | 104233100430444453 |
oct | 7146125000736003 |
9 | 1205810000078623 |
10 | 253311400000515 |
11 | 7379284153853a |
12 | 244b15433b6803 |
13 | ab462160a988c |
14 | 467a4a12dbd63 |
15 | 1e44326854bb0 |
hex | e662a803bc03 |
253311400000515 has 32 divisors (see below), whose sum is σ = 406097722368000. Its totient is φ = 134833181662080.
The previous prime is 253311400000513. The next prime is 253311400000541. The reversal of 253311400000515 is 515000004113352.
It is not a de Polignac number, because 253311400000515 - 21 = 253311400000513 is a prime.
It is not an unprimeable number, because it can be changed into a prime (253311400000513) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7244161 + ... + 23645309.
It is an arithmetic number, because the mean of its divisors is an integer number (12690553824000).
Almost surely, 2253311400000515 is an apocalyptic number.
253311400000515 is a deficient number, since it is larger than the sum of its proper divisors (152786322367485).
253311400000515 is a wasteful number, since it uses less digits than its factorization.
253311400000515 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16403187.
The product of its (nonzero) digits is 9000, while the sum is 30.
Adding to 253311400000515 its reverse (515000004113352), we get a palindrome (768311404113867).
The spelling of 253311400000515 in words is "two hundred fifty-three trillion, three hundred eleven billion, four hundred million, five hundred fifteen", and thus it is an aban number.
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