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2533120439 is a prime number
BaseRepresentation
bin1001011011111100…
…0101100110110111
320112112111211222112
42112333011212313
520141434323224
61055205321235
7116526111533
oct22677054667
96475454875
102533120439
11108a975973
125a840621b
13314a57845
141a05d2bc3
15ec5be30e
hex96fc59b7

2533120439 has 2 divisors, whose sum is σ = 2533120440. Its totient is φ = 2533120438.

The previous prime is 2533120423. The next prime is 2533120441. The reversal of 2533120439 is 9340213352.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2533120439 - 24 = 2533120423 is a prime.

Together with 2533120441, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2533120459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1266560219 + 1266560220.

It is an arithmetic number, because the mean of its divisors is an integer number (1266560220).

Almost surely, 22533120439 is an apocalyptic number.

2533120439 is a deficient number, since it is larger than the sum of its proper divisors (1).

2533120439 is an equidigital number, since it uses as much as digits as its factorization.

2533120439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 32.

The square root of 2533120439 is about 50330.1146332889. The cubic root of 2533120439 is about 1363.1760472311.

The spelling of 2533120439 in words is "two billion, five hundred thirty-three million, one hundred twenty thousand, four hundred thirty-nine".