Base | Representation |
---|---|
bin | 111001100111101000110011… |
… | …111110111100000000001000 |
3 | 1020020021000001002210201121102 |
4 | 321213220303332330000020 |
5 | 231203402331312112204 |
6 | 2254544035454200532 |
7 | 104243310536012612 |
oct | 7147506376740010 |
9 | 1206230032721542 |
10 | 253412532535304 |
11 | 7382171918a7aa |
12 | 245090684b3148 |
13 | ab5291241b93c |
14 | 4681336929db2 |
15 | 1e46c9520041e |
hex | e67a33fbc008 |
253412532535304 has 8 divisors (see below), whose sum is σ = 475148498503710. Its totient is φ = 126706266267648.
The previous prime is 253412532535291. The next prime is 253412532535397. The reversal of 253412532535304 is 403535235214352.
253412532535304 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 208278294422500 + 45134238112804 = 14431850^2 + 6718202^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15838283283449 + ... + 15838283283464.
Almost surely, 2253412532535304 is an apocalyptic number.
It is an amenable number.
253412532535304 is a deficient number, since it is larger than the sum of its proper divisors (221735965968406).
253412532535304 is a wasteful number, since it uses less digits than its factorization.
253412532535304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31676566566919 (or 31676566566915 counting only the distinct ones).
The product of its (nonzero) digits is 6480000, while the sum is 47.
Adding to 253412532535304 its reverse (403535235214352), we get a palindrome (656947767749656).
The spelling of 253412532535304 in words is "two hundred fifty-three trillion, four hundred twelve billion, five hundred thirty-two million, five hundred thirty-five thousand, three hundred four".
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