253415513211041 has 2 divisors, whose sum is σ = 253415513211042. Its totient is φ = 253415513211040.

The previous prime is 253415513211037. The next prime is 253415513211043. The reversal of 253415513211041 is 140112315514352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 154286110070416 + 99129403140625 = 12421196^2 + 9956375^2 .

It is a cyclic number.

It is not a de Polignac number, because 253415513211041 - 2² = 253415513211037 is a prime.

Together with 253415513211043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 253415513210986 and 253415513211004.

It is not a weakly prime, because it can be changed into another prime (253415513211043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126707756605520 + 126707756605521.

It is an arithmetic number, because the mean of its divisors is an integer number (126707756605521).

Almost surely, 2^{253415513211041} is an apocalyptic number.

It is an amenable number.

253415513211041 is a deficient number, since it is larger than the sum of its proper divisors (1).

253415513211041 is an equidigital number, since it uses as much as digits as its factorization.

253415513211041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 253415513211041 its reverse (140112315514352), we get a palindrome (393527828725393).

The spelling of 253415513211041 in words is "two hundred fifty-three trillion, four hundred fifteen billion, five hundred thirteen million, two hundred eleven thousand, forty-one".