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253444425134477 is a prime number
BaseRepresentation
bin111001101000000110100000…
…111011100011000110001101
31020020101001100202100121222012
4321220012200323203012031
5231204413140313300402
62255010432255231005
7104245520056435403
oct7150064073430615
91206331322317865
10253444425134477
11738341a4784585
1224513289218465
13ab55925925ab5
144682ac0473473
151e47a10074452
hexe681a0ee318d

253444425134477 has 2 divisors, whose sum is σ = 253444425134478. Its totient is φ = 253444425134476.

The previous prime is 253444425134447. The next prime is 253444425134479. The reversal of 253444425134477 is 774431524444352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 173667749029636 + 79776676104841 = 13178306^2 + 8931779^2 .

It is a cyclic number.

It is not a de Polignac number, because 253444425134477 - 212 = 253444425130381 is a prime.

Together with 253444425134479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253444425134479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126722212567238 + 126722212567239.

It is an arithmetic number, because the mean of its divisors is an integer number (126722212567239).

Almost surely, 2253444425134477 is an apocalyptic number.

It is an amenable number.

253444425134477 is a deficient number, since it is larger than the sum of its proper divisors (1).

253444425134477 is an equidigital number, since it uses as much as digits as its factorization.

253444425134477 is an evil number, because the sum of its binary digits is even.

The product of its digits is 180633600, while the sum is 59.

The spelling of 253444425134477 in words is "two hundred fifty-three trillion, four hundred forty-four billion, four hundred twenty-five million, one hundred thirty-four thousand, four hundred seventy-seven".