Base | Representation |
---|---|
bin | 1110110000011010010… |
… | …1000010000001000001 |
3 | 220020100210021011120111 |
4 | 3230012211002001001 |
5 | 13123143420110340 |
6 | 312243520511321 |
7 | 24213204460663 |
oct | 3540645020101 |
9 | 806323234514 |
10 | 253513441345 |
11 | 9857280178a |
12 | 4117117b541 |
13 | 1aba1c53578 |
14 | c3ad2ac533 |
15 | 68db4cdaea |
hex | 3b06942041 |
253513441345 has 8 divisors (see below), whose sum is σ = 314706341160. Its totient is φ = 195817278720.
The previous prime is 253513441331. The next prime is 253513441367. The reversal of 253513441345 is 543144315352.
It can be written as a sum of positive squares in 4 ways, for example, as 40929740721 + 212583700624 = 202311^2 + 461068^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 253513441345 - 213 = 253513433153 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 253513441298 and 253513441307.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 874184136 + ... + 874184425.
It is an arithmetic number, because the mean of its divisors is an integer number (39338292645).
Almost surely, 2253513441345 is an apocalyptic number.
It is an amenable number.
253513441345 is a deficient number, since it is larger than the sum of its proper divisors (61192899815).
253513441345 is a wasteful number, since it uses less digits than its factorization.
253513441345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1748368595.
The product of its digits is 432000, while the sum is 40.
Adding to 253513441345 its reverse (543144315352), we get a palindrome (796657756697).
The spelling of 253513441345 in words is "two hundred fifty-three billion, five hundred thirteen million, four hundred forty-one thousand, three hundred forty-five".
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