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253522120933 is a prime number
BaseRepresentation
bin1110110000011100011…
…0001001000011100101
3220020101101121010201201
43230013012021003211
513123203130332213
6312244430522501
724213341320624
oct3540706110345
9806341533651
10253522120933
119857769a8a4
1241174066431
131aba39a2113
14c3b04cb6bb
1568dc1456dd
hex3b071890e5

253522120933 has 2 divisors, whose sum is σ = 253522120934. Its totient is φ = 253522120932.

The previous prime is 253522120921. The next prime is 253522121003. The reversal of 253522120933 is 339021225352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 224014783204 + 29507337729 = 473302^2 + 171777^2 .

It is a cyclic number.

It is not a de Polignac number, because 253522120933 - 237 = 116083167461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253522120892 and 253522120901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253522121933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126761060466 + 126761060467.

It is an arithmetic number, because the mean of its divisors is an integer number (126761060467).

Almost surely, 2253522120933 is an apocalyptic number.

It is an amenable number.

253522120933 is a deficient number, since it is larger than the sum of its proper divisors (1).

253522120933 is an equidigital number, since it uses as much as digits as its factorization.

253522120933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 37.

The spelling of 253522120933 in words is "two hundred fifty-three billion, five hundred twenty-two million, one hundred twenty thousand, nine hundred thirty-three".