253945000543 has 8 divisors (see below), whose sum is σ = 273487633328. Its totient is φ = 234403568064.

The previous prime is 253945000513. The next prime is 253945000559. The reversal of 253945000543 is 345000549352.

253945000543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 253945000543 - 2¹³ = 253944992351 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253945000496 and 253945000505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253945000513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 166180 + ... + 731782.

It is an arithmetic number, because the mean of its divisors is an integer number (34185954166).

Almost surely, 2^253945000543 is an apocalyptic number.

253945000543 is a deficient number, since it is larger than the sum of its proper divisors (19542632785).

253945000543 is a wasteful number, since it uses less digits than its factorization.

253945000543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600153.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 253945000543 its reverse (345000549352), we get a palindrome (598945549895).

The spelling of 253945000543 in words is "two hundred fifty-three billion, nine hundred forty-five million, five hundred forty-three", and thus it is an aban number.