254012531 has 2 divisors, whose sum is σ = 254012532. Its totient is φ = 254012530.

The previous prime is 254012491. The next prime is 254012557. The reversal of 254012531 is 135210452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 254012531 - 2¹⁰ = 254011507 is a prime.

It is a super-2 number, since 2×254012531² = 129044731810051922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 254012497 and 254012506.

It is not a weakly prime, because it can be changed into another prime (254612531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127006265 + 127006266.

It is an arithmetic number, because the mean of its divisors is an integer number (127006266).

Almost surely, 2^254012531 is an apocalyptic number.

254012531 is a deficient number, since it is larger than the sum of its proper divisors (1).

254012531 is an equidigital number, since it uses as much as digits as its factorization.

254012531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 254012531 is about 15937.7705780953. The cubic root of 254012531 is about 633.3129675507.

Adding to 254012531 its reverse (135210452), we get a palindrome (389222983).

The spelling of 254012531 in words is "two hundred fifty-four million, twelve thousand, five hundred thirty-one".