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2540312234335 = 55916751564239
BaseRepresentation
bin100100111101110110011…
…010001000100101011111
322222211222201122020200201
4210331312122020211133
5313110024412444320
65223000415204331
7351350206501411
oct44756632104537
98884881566621
102540312234335
1189a382037627
123503b55166a7
13155720357035
148ad4791a9b1
154612cc2170a
hex24f7668895f

2540312234335 has 16 divisors (see below), whose sum is σ = 3118605235200. Its totient is φ = 1985841933856.

The previous prime is 2540312234261. The next prime is 2540312234413. The reversal of 2540312234335 is 5334322130452.

It is a cyclic number.

It is not a de Polignac number, because 2540312234335 - 213 = 2540312226143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2540312234294 and 2540312234303.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25732855 + ... + 25831384.

It is an arithmetic number, because the mean of its divisors is an integer number (194912827200).

Almost surely, 22540312234335 is an apocalyptic number.

2540312234335 is a deficient number, since it is larger than the sum of its proper divisors (578293000865).

2540312234335 is a wasteful number, since it uses less digits than its factorization.

2540312234335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51564470.

The product of its (nonzero) digits is 259200, while the sum is 37.

Adding to 2540312234335 its reverse (5334322130452), we get a palindrome (7874634364787).

The spelling of 2540312234335 in words is "two trillion, five hundred forty billion, three hundred twelve million, two hundred thirty-four thousand, three hundred thirty-five".

Divisors: 1 5 59 167 295 835 9853 49265 51564239 257821195 3042290101 8611227913 15211450505 43056139565 508062446867 2540312234335