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2540433101 = 11719216779
BaseRepresentation
bin1001011101101011…
…1110111011001101
320120001021101001212
42113122332323031
520200322324401
61100030144205
7116645216333
oct22732767315
96501241055
102540433101
11109400aa98
125aa952065
1331641816b
141a1577b53
15ed065dbb
hex976beecd

2540433101 has 4 divisors (see below), whose sum is σ = 2540661600. Its totient is φ = 2540204604.

The previous prime is 2540433011. The next prime is 2540433107. The reversal of 2540433101 is 1013340452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2540433101 - 222 = 2536238797 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2540433107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96671 + ... + 120108.

It is an arithmetic number, because the mean of its divisors is an integer number (635165400).

Almost surely, 22540433101 is an apocalyptic number.

It is an amenable number.

2540433101 is a deficient number, since it is larger than the sum of its proper divisors (228499).

2540433101 is a wasteful number, since it uses less digits than its factorization.

2540433101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228498.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 2540433101 is about 50402.7092624990. The cubic root of 2540433101 is about 1364.4865348170.

Adding to 2540433101 its reverse (1013340452), we get a palindrome (3553773553).

The spelling of 2540433101 in words is "two billion, five hundred forty million, four hundred thirty-three thousand, one hundred one".

Divisors: 1 11719 216779 2540433101