Base | Representation |
---|---|
bin | 111001110001110010100100… |
… | …001101100100111010101111 |
3 | 1020022201200211202110022020111 |
4 | 321301302210031210322233 |
5 | 231301320142212414210 |
6 | 2300240340412000451 |
7 | 104344566434451463 |
oct | 7161624415447257 |
9 | 1208650752408214 |
10 | 254110200123055 |
11 | 73a7059236a571 |
12 | 24600313a60127 |
13 | aba36485a5793 |
14 | 46a6ddc1664a3 |
15 | 1e59ec963288a |
hex | e71ca4364eaf |
254110200123055 has 4 divisors (see below), whose sum is σ = 304932240147672. Its totient is φ = 203288160098440.
The previous prime is 254110200123047. The next prime is 254110200123089. The reversal of 254110200123055 is 550321002011452.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 254110200123055 - 23 = 254110200123047 is a prime.
It is a super-2 number, since 2×2541102001230552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25411020012301 + ... + 25411020012310.
It is an arithmetic number, because the mean of its divisors is an integer number (76233060036918).
Almost surely, 2254110200123055 is an apocalyptic number.
254110200123055 is a deficient number, since it is larger than the sum of its proper divisors (50822040024617).
254110200123055 is an equidigital number, since it uses as much as digits as its factorization.
254110200123055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50822040024616.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 254110200123055 in words is "two hundred fifty-four trillion, one hundred ten billion, two hundred million, one hundred twenty-three thousand, fifty-five".
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