Base | Representation |
---|---|
bin | 11110010010101… |
… | …11010001111101 |
3 | 122201011021100122 |
4 | 33021113101331 |
5 | 1010023103033 |
6 | 41114304325 |
7 | 6203631626 |
oct | 1711272175 |
9 | 581137318 |
10 | 254112893 |
11 | 120492861 |
12 | 711280a5 |
13 | 40852778 |
14 | 25a6aa4d |
15 | 17497a98 |
hex | f25747d |
254112893 has 2 divisors, whose sum is σ = 254112894. Its totient is φ = 254112892.
The previous prime is 254112863. The next prime is 254113001. The reversal of 254112893 is 398211452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 208455844 + 45657049 = 14438^2 + 6757^2 .
It is a cyclic number.
It is not a de Polignac number, because 254112893 - 214 = 254096509 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254112863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127056446 + 127056447.
It is an arithmetic number, because the mean of its divisors is an integer number (127056447).
Almost surely, 2254112893 is an apocalyptic number.
It is an amenable number.
254112893 is a deficient number, since it is larger than the sum of its proper divisors (1).
254112893 is an equidigital number, since it uses as much as digits as its factorization.
254112893 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 35.
The square root of 254112893 is about 15940.9188254630. The cubic root of 254112893 is about 633.3963652563.
The spelling of 254112893 in words is "two hundred fifty-four million, one hundred twelve thousand, eight hundred ninety-three".
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