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254113241 is a prime number
BaseRepresentation
bin11110010010101…
…11010111011001
3122201011021211112
433021113113121
51010023110431
641114310105
76203632634
oct1711272731
9581137745
10254113241
11120493048
1271128335
1340852985
1425a6ac1b
1517497c2b
hexf2575d9

254113241 has 2 divisors, whose sum is σ = 254113242. Its totient is φ = 254113240.

The previous prime is 254113213. The next prime is 254113247. The reversal of 254113241 is 142311452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132342016 + 121771225 = 11504^2 + 11035^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-254113241 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (254113247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127056620 + 127056621.

It is an arithmetic number, because the mean of its divisors is an integer number (127056621).

Almost surely, 2254113241 is an apocalyptic number.

It is an amenable number.

254113241 is a deficient number, since it is larger than the sum of its proper divisors (1).

254113241 is an equidigital number, since it uses as much as digits as its factorization.

254113241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 960, while the sum is 23.

The square root of 254113241 is about 15940.9297407648. The cubic root of 254113241 is about 633.3966543953.

Adding to 254113241 its reverse (142311452), we get a palindrome (396424693).

The spelling of 254113241 in words is "two hundred fifty-four million, one hundred thirteen thousand, two hundred forty-one".