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254132400311327 is a prime number
BaseRepresentation
bin111001110010000111001111…
…011100100100110000011111
31020022210211010221000201101202
4321302013033130210300133
5231302201123434430302
62300254451335030115
7104346313534110446
oct7162071734446037
91208724127021352
10254132400311327
1173a79a448375aa
122460468a80b33b
13aba5775a49665
1446a8106737d5d
151e5a878606202
hexe721cf724c1f

254132400311327 has 2 divisors, whose sum is σ = 254132400311328. Its totient is φ = 254132400311326.

The previous prime is 254132400311287. The next prime is 254132400311329. The reversal of 254132400311327 is 723113004231452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 254132400311327 - 232 = 254128105344031 is a prime.

Together with 254132400311329, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254132400311329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127066200155663 + 127066200155664.

It is an arithmetic number, because the mean of its divisors is an integer number (127066200155664).

Almost surely, 2254132400311327 is an apocalyptic number.

254132400311327 is a deficient number, since it is larger than the sum of its proper divisors (1).

254132400311327 is an equidigital number, since it uses as much as digits as its factorization.

254132400311327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 254132400311327 its reverse (723113004231452), we get a palindrome (977245404542779).

The spelling of 254132400311327 in words is "two hundred fifty-four trillion, one hundred thirty-two billion, four hundred million, three hundred eleven thousand, three hundred twenty-seven".