Base | Representation |
---|---|
bin | 111001110010000111010001… |
… | …110100100001001001010111 |
3 | 1020022210211020200222100101112 |
4 | 321302013101310201021113 |
5 | 231302201214134024143 |
6 | 2300254455320445235 |
7 | 104346314526503213 |
oct | 7162072164411127 |
9 | 1208724220870345 |
10 | 254132440142423 |
11 | 73a79a65272267 |
12 | 246046a001981b |
13 | aba578108435b |
14 | 46a810bb45943 |
15 | 1e5a87bd72e18 |
hex | e721d1d21257 |
254132440142423 has 2 divisors, whose sum is σ = 254132440142424. Its totient is φ = 254132440142422.
The previous prime is 254132440142297. The next prime is 254132440142429. The reversal of 254132440142423 is 324241044231452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 254132440142423 - 212 = 254132440138327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254132440142429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127066220071211 + 127066220071212.
It is an arithmetic number, because the mean of its divisors is an integer number (127066220071212).
Almost surely, 2254132440142423 is an apocalyptic number.
254132440142423 is a deficient number, since it is larger than the sum of its proper divisors (1).
254132440142423 is an equidigital number, since it uses as much as digits as its factorization.
254132440142423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 737280, while the sum is 41.
Adding to 254132440142423 its reverse (324241044231452), we get a palindrome (578373484373875).
The spelling of 254132440142423 in words is "two hundred fifty-four trillion, one hundred thirty-two billion, four hundred forty million, one hundred forty-two thousand, four hundred twenty-three".
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