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25422200341113 = 38474066780371
BaseRepresentation
bin1011100011111000100010…
…01110001000001001111001
310100000100010212000011212210
411301330101032020021321
511313004131241403423
6130022444141125333
75232456552331452
oct561742116101171
9110010125004783
1025422200341113
118111549378844
122a26bab559849
1311253c31b1944
1463c6263b8129
152e1452ea4b93
hex171f11388279

25422200341113 has 4 divisors (see below), whose sum is σ = 33896267121488. Its totient is φ = 16948133560740.

The previous prime is 25422200341067. The next prime is 25422200341121. The reversal of 25422200341113 is 31114300222452.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 25422200341113 - 221 = 25422198243961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25422200341123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4237033390183 + ... + 4237033390188.

It is an arithmetic number, because the mean of its divisors is an integer number (8474066780372).

Almost surely, 225422200341113 is an apocalyptic number.

It is an amenable number.

25422200341113 is a deficient number, since it is larger than the sum of its proper divisors (8474066780375).

25422200341113 is an equidigital number, since it uses as much as digits as its factorization.

25422200341113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8474066780374.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 25422200341113 its reverse (31114300222452), we get a palindrome (56536500563565).

The spelling of 25422200341113 in words is "twenty-five trillion, four hundred twenty-two billion, two hundred million, three hundred forty-one thousand, one hundred thirteen".

Divisors: 1 3 8474066780371 25422200341113