Base | Representation |
---|---|
bin | 10111101011011010… |
… | …001011000000111101 |
3 | 2102121212101110010002 |
4 | 113223122023000331 |
5 | 404032112434401 |
6 | 15402455524045 |
7 | 1560016231163 |
oct | 275332130075 |
9 | 72555343102 |
10 | 25424343101 |
11 | a867419303 |
12 | 4b16689625 |
13 | 252241c001 |
14 | 1332887233 |
15 | 9dc093a6b |
hex | 5eb68b03d |
25424343101 has 2 divisors, whose sum is σ = 25424343102. Its totient is φ = 25424343100.
The previous prime is 25424343097. The next prime is 25424343103. The reversal of 25424343101 is 10134342452.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21408079225 + 4016263876 = 146315^2 + 63374^2 .
It is a cyclic number.
It is not a de Polignac number, because 25424343101 - 22 = 25424343097 is a prime.
Together with 25424343103, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25424343103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12712171550 + 12712171551.
It is an arithmetic number, because the mean of its divisors is an integer number (12712171551).
Almost surely, 225424343101 is an apocalyptic number.
It is an amenable number.
25424343101 is a deficient number, since it is larger than the sum of its proper divisors (1).
25424343101 is an equidigital number, since it uses as much as digits as its factorization.
25424343101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 25424343101 its reverse (10134342452), we get a palindrome (35558685553).
The spelling of 25424343101 in words is "twenty-five billion, four hundred twenty-four million, three hundred forty-three thousand, one hundred one".
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