Base | Representation |
---|---|
bin | 1011100100001000000101… |
… | …01000001010101001111111 |
3 | 10100001010200102210022012022 |
4 | 11302010002220022221333 |
5 | 11313123224113142310 |
6 | 130030344205430355 |
7 | 5233203423460055 |
oct | 562040250125177 |
9 | 110033612708168 |
10 | 25430545443455 |
11 | 8115040a25739 |
12 | 2a2873a26b3bb |
13 | 1126123084919 |
14 | 63cbb88361d5 |
15 | 2e179091ca55 |
hex | 172102a0aa7f |
25430545443455 has 4 divisors (see below), whose sum is σ = 30516654532152. Its totient is φ = 20344436354760.
The previous prime is 25430545443431. The next prime is 25430545443571. The reversal of 25430545443455 is 55434454503452.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-25430545443455 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25430545443397 and 25430545443406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2543054544341 + ... + 2543054544350.
It is an arithmetic number, because the mean of its divisors is an integer number (7629163633038).
Almost surely, 225430545443455 is an apocalyptic number.
25430545443455 is a deficient number, since it is larger than the sum of its proper divisors (5086109088697).
25430545443455 is an equidigital number, since it uses as much as digits as its factorization.
25430545443455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5086109088696.
The product of its (nonzero) digits is 57600000, while the sum is 53.
The spelling of 25430545443455 in words is "twenty-five trillion, four hundred thirty billion, five hundred forty-five million, four hundred forty-three thousand, four hundred fifty-five".
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