Base | Representation |
---|---|
bin | 1011100101111011000010… |
… | …00110001011110110100001 |
3 | 10100021000222102110012012001 |
4 | 11302331201012023312201 |
5 | 11320131122014204441 |
6 | 130114552121004001 |
7 | 5240516652013441 |
oct | 562754106136641 |
9 | 110230872405161 |
10 | 25492259913121 |
11 | 8139230159181 |
12 | 2a386a2323601 |
13 | 112bba9a864b1 |
14 | 641b90c9a121 |
15 | 2e31a3931731 |
hex | 172f6118bda1 |
25492259913121 has 4 divisors (see below), whose sum is σ = 25492589607600. Its totient is φ = 25491930218644.
The previous prime is 25492259913119. The next prime is 25492259913139. The reversal of 25492259913121 is 12131995229452.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25492259913121 - 21 = 25492259913119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25492659913121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164731231 + ... + 164885908.
It is an arithmetic number, because the mean of its divisors is an integer number (6373147401900).
Almost surely, 225492259913121 is an apocalyptic number.
It is an amenable number.
25492259913121 is a deficient number, since it is larger than the sum of its proper divisors (329694479).
25492259913121 is an equidigital number, since it uses as much as digits as its factorization.
25492259913121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 329694478.
The product of its digits is 3499200, while the sum is 55.
The spelling of 25492259913121 in words is "twenty-five trillion, four hundred ninety-two billion, two hundred fifty-nine million, nine hundred thirteen thousand, one hundred twenty-one".
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