Base | Representation |
---|---|
bin | 1110110101111111100… |
… | …0001001010100010101 |
3 | 220101020012100202002212 |
4 | 3231133320021110111 |
5 | 13134230433433323 |
6 | 313052320043205 |
7 | 24265266020033 |
oct | 3553770112425 |
9 | 811205322085 |
10 | 255011624213 |
11 | 99171460745 |
12 | 4150aa63505 |
13 | 1b08045a6c8 |
14 | c4b225b553 |
15 | 6977cb9b78 |
hex | 3b5fe09515 |
255011624213 has 2 divisors, whose sum is σ = 255011624214. Its totient is φ = 255011624212.
The previous prime is 255011624143. The next prime is 255011624251. The reversal of 255011624213 is 312426110552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 200669953444 + 54341670769 = 447962^2 + 233113^2 .
It is a cyclic number.
It is not a de Polignac number, because 255011624213 - 228 = 254743188757 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 255011624213.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255011621213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127505812106 + 127505812107.
It is an arithmetic number, because the mean of its divisors is an integer number (127505812107).
Almost surely, 2255011624213 is an apocalyptic number.
It is an amenable number.
255011624213 is a deficient number, since it is larger than the sum of its proper divisors (1).
255011624213 is an equidigital number, since it uses as much as digits as its factorization.
255011624213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 255011624213 its reverse (312426110552), we get a palindrome (567437734765).
The spelling of 255011624213 in words is "two hundred fifty-five billion, eleven million, six hundred twenty-four thousand, two hundred thirteen".
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