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255011624143 is a prime number
BaseRepresentation
bin1110110101111111100…
…0001001010011001111
3220101020012100202000021
43231133320021103033
513134230433433033
6313052320043011
724265266016603
oct3553770112317
9811205322007
10255011624143
1199171460691
124150aa63467
131b08045a673
14c4b225b503
156977cb9b2d
hex3b5fe094cf

255011624143 has 2 divisors, whose sum is σ = 255011624144. Its totient is φ = 255011624142.

The previous prime is 255011624129. The next prime is 255011624213. The reversal of 255011624143 is 341426110552.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255011624143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255011624099 and 255011624108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255011624123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127505812071 + 127505812072.

It is an arithmetic number, because the mean of its divisors is an integer number (127505812072).

Almost surely, 2255011624143 is an apocalyptic number.

255011624143 is a deficient number, since it is larger than the sum of its proper divisors (1).

255011624143 is an equidigital number, since it uses as much as digits as its factorization.

255011624143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 255011624143 its reverse (341426110552), we get a palindrome (596437734695).

The spelling of 255011624143 in words is "two hundred fifty-five billion, eleven million, six hundred twenty-four thousand, one hundred forty-three".