Base | Representation |
---|---|
bin | 1110110101111111100… |
… | …0001001010011001111 |
3 | 220101020012100202000021 |
4 | 3231133320021103033 |
5 | 13134230433433033 |
6 | 313052320043011 |
7 | 24265266016603 |
oct | 3553770112317 |
9 | 811205322007 |
10 | 255011624143 |
11 | 99171460691 |
12 | 4150aa63467 |
13 | 1b08045a673 |
14 | c4b225b503 |
15 | 6977cb9b2d |
hex | 3b5fe094cf |
255011624143 has 2 divisors, whose sum is σ = 255011624144. Its totient is φ = 255011624142.
The previous prime is 255011624129. The next prime is 255011624213. The reversal of 255011624143 is 341426110552.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255011624143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255011624099 and 255011624108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255011624123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127505812071 + 127505812072.
It is an arithmetic number, because the mean of its divisors is an integer number (127505812072).
Almost surely, 2255011624143 is an apocalyptic number.
255011624143 is a deficient number, since it is larger than the sum of its proper divisors (1).
255011624143 is an equidigital number, since it uses as much as digits as its factorization.
255011624143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 255011624143 its reverse (341426110552), we get a palindrome (596437734695).
The spelling of 255011624143 in words is "two hundred fifty-five billion, eleven million, six hundred twenty-four thousand, one hundred forty-three".
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