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2550117 = 3899551
BaseRepresentation
bin1001101110100101100101
311210120002210
421232211211
51123100432
6130354033
730450513
oct11564545
94716083
102550117
111491a39
12a2b919
136b395b
144a54b3
153558cc
hex26e965

2550117 has 8 divisors (see below), whose sum is σ = 3438720. Its totient is φ = 1680800.

The previous prime is 2550101. The next prime is 2550133. The reversal of 2550117 is 7110552.

It is an interprime number because it is at equal distance from previous prime (2550101) and next prime (2550133).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2550117 - 24 = 2550101 is a prime.

2550117 is a lucky number.

It is a plaindrome in base 15.

It is a junction number, because it is equal to n+sod(n) for n = 2550093 and 2550102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2550167) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4509 + ... + 5042.

It is an arithmetic number, because the mean of its divisors is an integer number (429840).

22550117 is an apocalyptic number.

It is an amenable number.

2550117 is a deficient number, since it is larger than the sum of its proper divisors (888603).

2550117 is an equidigital number, since it uses as much as digits as its factorization.

2550117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9643.

The product of its (nonzero) digits is 350, while the sum is 21.

The square root of 2550117 is about 1596.9085759680. The cubic root of 2550117 is about 136.6218102509.

Adding to 2550117 its reverse (7110552), we get a palindrome (9660669).

The spelling of 2550117 in words is "two million, five hundred fifty thousand, one hundred seventeen".

Divisors: 1 3 89 267 9551 28653 850039 2550117