25503471137 has 2 divisors, whose sum is σ = 25503471138. Its totient is φ = 25503471136.

The previous prime is 25503471109. The next prime is 25503471139. The reversal of 25503471137 is 73117430552.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25341774481 + 161696656 = 159191^2 + 12716^2 .

It is a cyclic number.

It is not a de Polignac number, because 25503471137 - 2¹⁸ = 25503208993 is a prime.

Together with 25503471139, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25503471137.

It is not a weakly prime, because it can be changed into another prime (25503471139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12751735568 + 12751735569.

It is an arithmetic number, because the mean of its divisors is an integer number (12751735569).

Almost surely, 2^25503471137 is an apocalyptic number.

It is an amenable number.

25503471137 is a deficient number, since it is larger than the sum of its proper divisors (1).

25503471137 is an equidigital number, since it uses as much as digits as its factorization.

25503471137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 88200, while the sum is 38.

The spelling of 25503471137 in words is "twenty-five billion, five hundred three million, four hundred seventy-one thousand, one hundred thirty-seven".