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2550398047 is a prime number
BaseRepresentation
bin1001100000000011…
…1111110001011111
320120202000122101221
42120000333301133
520210400214142
61101023514211
7120126011551
oct23000776137
96522018357
102550398047
1110996a688a
125b2158967
133184c6a92
141a2a0d4d1
15edd83767
hex9803fc5f

2550398047 has 2 divisors, whose sum is σ = 2550398048. Its totient is φ = 2550398046.

The previous prime is 2550398041. The next prime is 2550398087. The reversal of 2550398047 is 7408930552.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2550398047 - 211 = 2550395999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2550397994 and 2550398012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2550398041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275199023 + 1275199024.

It is an arithmetic number, because the mean of its divisors is an integer number (1275199024).

Almost surely, 22550398047 is an apocalyptic number.

2550398047 is a deficient number, since it is larger than the sum of its proper divisors (1).

2550398047 is an equidigital number, since it uses as much as digits as its factorization.

2550398047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 43.

The square root of 2550398047 is about 50501.4657906085. The cubic root of 2550398047 is about 1366.2682907148.

The spelling of 2550398047 in words is "two billion, five hundred fifty million, three hundred ninety-eight thousand, forty-seven".