Base | Representation |
---|---|
bin | 1011100110010011001010… |
… | …00010101101111110111111 |
3 | 10100022021102000020100011211 |
4 | 11303021211002231332333 |
5 | 11320334133004440403 |
6 | 130124533204025251 |
7 | 5241455622403321 |
oct | 563114502557677 |
9 | 110267360210154 |
10 | 25505211015103 |
11 | 8143776775846 |
12 | 2a3b0b7692227 |
13 | 1130191c97551 |
14 | 64265cd37611 |
15 | 2e36b092506d |
hex | 1732650adfbf |
25505211015103 has 2 divisors, whose sum is σ = 25505211015104. Its totient is φ = 25505211015102.
The previous prime is 25505211015101. The next prime is 25505211015133. The reversal of 25505211015103 is 30151011250552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25505211015103 - 21 = 25505211015101 is a prime.
Together with 25505211015101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25505211015101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12752605507551 + 12752605507552.
It is an arithmetic number, because the mean of its divisors is an integer number (12752605507552).
Almost surely, 225505211015103 is an apocalyptic number.
25505211015103 is a deficient number, since it is larger than the sum of its proper divisors (1).
25505211015103 is an equidigital number, since it uses as much as digits as its factorization.
25505211015103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7500, while the sum is 31.
Adding to 25505211015103 its reverse (30151011250552), we get a palindrome (55656222265655).
The spelling of 25505211015103 in words is "twenty-five trillion, five hundred five billion, two hundred eleven million, fifteen thousand, one hundred three".
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