Base | Representation |
---|---|
bin | 1110110110001001111… |
… | …1001100001101011111 |
3 | 220101100020202111112221 |
4 | 3231202133030031133 |
5 | 13134323141222421 |
6 | 313100522410211 |
7 | 24266340151261 |
oct | 3554237141537 |
9 | 811306674487 |
10 | 255055414111 |
11 | 9919414a743 |
12 | 41521660967 |
13 | 1b0895502a4 |
14 | c4b7db9b31 |
15 | 697ba69841 |
hex | 3b627cc35f |
255055414111 has 4 divisors (see below), whose sum is σ = 255056537824. Its totient is φ = 255054290400.
The previous prime is 255055414073. The next prime is 255055414121. The reversal of 255055414111 is 111414550552.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 255055414111 - 231 = 252907930463 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255055414121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88410 + ... + 719671.
It is an arithmetic number, because the mean of its divisors is an integer number (63764134456).
Almost surely, 2255055414111 is an apocalyptic number.
255055414111 is a deficient number, since it is larger than the sum of its proper divisors (1123713).
255055414111 is an equidigital number, since it uses as much as digits as its factorization.
255055414111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1123712.
The product of its (nonzero) digits is 20000, while the sum is 34.
Adding to 255055414111 its reverse (111414550552), we get a palindrome (366469964663).
The spelling of 255055414111 in words is "two hundred fifty-five billion, fifty-five million, four hundred fourteen thousand, one hundred eleven".
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