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255104111211311 is a prime number
BaseRepresentation
bin111010000000010000001101…
…111011011111001100101111
31020110020201022010111222001202
4322000100031323133030233
5231414111204432230221
62302321113312000115
7104506443455351315
oct7200201573371457
91213221263458052
10255104111211311
117431405625699a
1224740a7683003b
13ac462a3244a5b
1446dd167a580b5
151e75c9b54bd0b
hexe8040dedf32f

255104111211311 has 2 divisors, whose sum is σ = 255104111211312. Its totient is φ = 255104111211310.

The previous prime is 255104111211307. The next prime is 255104111211353. The reversal of 255104111211311 is 113112111401552.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255104111211311 - 22 = 255104111211307 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255104110211311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127552055605655 + 127552055605656.

It is an arithmetic number, because the mean of its divisors is an integer number (127552055605656).

Almost surely, 2255104111211311 is an apocalyptic number.

255104111211311 is a deficient number, since it is larger than the sum of its proper divisors (1).

255104111211311 is an equidigital number, since it uses as much as digits as its factorization.

255104111211311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 29.

Adding to 255104111211311 its reverse (113112111401552), we get a palindrome (368216222612863).

The spelling of 255104111211311 in words is "two hundred fifty-five trillion, one hundred four billion, one hundred eleven million, two hundred eleven thousand, three hundred eleven".