Base | Representation |
---|---|
bin | 111010000000010000001110… |
… | …011111000111111001011111 |
3 | 1020110020201022210002120112021 |
4 | 322000100032133013321133 |
5 | 231414111214330144210 |
6 | 2302321114244121011 |
7 | 104506443630636604 |
oct | 7200201637077137 |
9 | 1213221283076467 |
10 | 255104120553055 |
11 | 74314060557544 |
12 | 24740a79996167 |
13 | ac462a5165b07 |
14 | 46dd168daa6ab |
15 | 1e75c9c294bda |
hex | e8040e7c7e5f |
255104120553055 has 32 divisors (see below), whose sum is σ = 324367466492160. Its totient is φ = 191939081832960.
The previous prime is 255104120553049. The next prime is 255104120553059. The reversal of 255104120553055 is 550355021401552.
It is not a de Polignac number, because 255104120553055 - 27 = 255104120552927 is a prime.
It is a super-2 number, since 2×2551041205530552 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255104120553059) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 714761436 + ... + 715118254.
It is an arithmetic number, because the mean of its divisors is an integer number (10136483327880).
Almost surely, 2255104120553055 is an apocalyptic number.
255104120553055 is a deficient number, since it is larger than the sum of its proper divisors (69263345939105).
255104120553055 is a wasteful number, since it uses less digits than its factorization.
255104120553055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 362919.
The product of its (nonzero) digits is 750000, while the sum is 43.
The spelling of 255104120553055 in words is "two hundred fifty-five trillion, one hundred four billion, one hundred twenty million, five hundred fifty-three thousand, fifty-five".
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