25511000117 has 2 divisors, whose sum is σ = 25511000118. Its totient is φ = 25511000116.

The previous prime is 25511000113. The next prime is 25511000153. The reversal of 25511000117 is 71100011552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23967374596 + 1543625521 = 154814^2 + 39289^2 .

It is a cyclic number.

It is not a de Polignac number, because 25511000117 - 2² = 25511000113 is a prime.

It is a super-2 number, since 2×25511000117² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25511000092 and 25511000101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25511000113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12755500058 + 12755500059.

It is an arithmetic number, because the mean of its divisors is an integer number (12755500059).

Almost surely, 2^25511000117 is an apocalyptic number.

It is an amenable number.

25511000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

25511000117 is an equidigital number, since it uses as much as digits as its factorization.

25511000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 350, while the sum is 23.

Adding to 25511000117 its reverse (71100011552), we get a palindrome (96611011669).

The spelling of 25511000117 in words is "twenty-five billion, five hundred eleven million, one hundred seventeen", and thus it is an aban number.