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255110202104053 = 1734994288791791
BaseRepresentation
bin111010000000010101111000…
…111110011001100011110101
31020110021022000121121101010211
4322000111320332121203311
5231414211143214312203
62302324001532545421
7104510050425161152
oct7200257076314365
91213238017541124
10255110202104053
11743166a141884a
1224742096622271
13ac46a340b5bba
1446dd584967229
151e7600613ac6d
hexe80578f998f5

255110202104053 has 8 divisors (see below), whose sum is σ = 270193882896000. Its totient is φ = 240035098902720.

The previous prime is 255110202103963. The next prime is 255110202104071. The reversal of 255110202104053 is 350401202011552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-255110202104053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255110202704053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2144336413 + ... + 2144455378.

It is an arithmetic number, because the mean of its divisors is an integer number (33774235362000).

Almost surely, 2255110202104053 is an apocalyptic number.

It is an amenable number.

255110202104053 is a deficient number, since it is larger than the sum of its proper divisors (15083680791947).

255110202104053 is a wasteful number, since it uses less digits than its factorization.

255110202104053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4288795307.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 255110202104053 in words is "two hundred fifty-five trillion, one hundred ten billion, two hundred two million, one hundred four thousand, fifty-three".

Divisors: 1 17 3499 59483 4288791791 72909460447 15006482476709 255110202104053