Base | Representation |
---|---|
bin | 1001100000001111… |
… | …0011001101101011 |
3 | 20120210101222121201 |
4 | 2120003303031223 |
5 | 20211042224120 |
6 | 1101051345031 |
7 | 120135162433 |
oct | 23003631553 |
9 | 6523358551 |
10 | 2551133035 |
11 | 109a059010 |
12 | 5b2452177 |
13 | 3186c3499 |
14 | 1a2b612c3 |
15 | ede7b40a |
hex | 980f336b |
2551133035 has 16 divisors (see below), whose sum is σ = 3360948192. Its totient is φ = 1843545600.
The previous prime is 2551132993. The next prime is 2551133047. The reversal of 2551133035 is 5303311552.
2551133035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2551133035 - 219 = 2550608747 is a prime.
It is a super-2 number, since 2×25511330352 = 13016559524536622450, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2551132994 and 2551133012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139086 + ... + 156355.
It is an arithmetic number, because the mean of its divisors is an integer number (210059262).
Almost surely, 22551133035 is an apocalyptic number.
2551133035 is a deficient number, since it is larger than the sum of its proper divisors (809815157).
2551133035 is a wasteful number, since it uses less digits than its factorization.
2551133035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 295614.
The product of its (nonzero) digits is 6750, while the sum is 28.
The square root of 2551133035 is about 50508.7421641046. The cubic root of 2551133035 is about 1366.3995243930.
Adding to 2551133035 its reverse (5303311552), we get a palindrome (7854444587).
The spelling of 2551133035 in words is "two billion, five hundred fifty-one million, one hundred thirty-three thousand, thirty-five".
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