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2551487051 is a prime number
BaseRepresentation
bin1001100000010100…
…1001101001001011
320120211001222020102
42120011021221023
520211140041201
61101103120015
7120141165521
oct23005115113
96524058212
102551487051
11109a27aa93
125b25a300b
133187b8669
141a2c14311
15edeeb26b
hex98149a4b

2551487051 has 2 divisors, whose sum is σ = 2551487052. Its totient is φ = 2551487050.

The previous prime is 2551487017. The next prime is 2551487053. The reversal of 2551487051 is 1507841552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2551487051 - 226 = 2484378187 is a prime.

It is a super-3 number, since 3×25514870513 (a number of 29 digits) contains 333 as substring.

Together with 2551487053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2551486996 and 2551487014.

It is not a weakly prime, because it can be changed into another prime (2551487053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275743525 + 1275743526.

It is an arithmetic number, because the mean of its divisors is an integer number (1275743526).

Almost surely, 22551487051 is an apocalyptic number.

2551487051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2551487051 is an equidigital number, since it uses as much as digits as its factorization.

2551487051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56000, while the sum is 38.

The square root of 2551487051 is about 50512.2465447737. The cubic root of 2551487051 is about 1366.4627257122.

The spelling of 2551487051 in words is "two billion, five hundred fifty-one million, four hundred eighty-seven thousand, fifty-one".