Base | Representation |
---|---|
bin | 1110110110100000110… |
… | …1000001010001010111 |
3 | 220101120221012201110221 |
4 | 3231220031001101113 |
5 | 13140022214022012 |
6 | 313114230055211 |
7 | 24301613245642 |
oct | 3555015012127 |
9 | 811527181427 |
10 | 255151314007 |
11 | 992332a0757 |
12 | 415497aa507 |
13 | 1b0a33897a5 |
14 | c4c6a20a59 |
15 | 69851ae507 |
hex | 3b68341457 |
255151314007 has 2 divisors, whose sum is σ = 255151314008. Its totient is φ = 255151314006.
The previous prime is 255151313999. The next prime is 255151314053. The reversal of 255151314007 is 700413151552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255151314007 - 23 = 255151313999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255151314097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127575657003 + 127575657004.
It is an arithmetic number, because the mean of its divisors is an integer number (127575657004).
Almost surely, 2255151314007 is an apocalyptic number.
255151314007 is a deficient number, since it is larger than the sum of its proper divisors (1).
255151314007 is an equidigital number, since it uses as much as digits as its factorization.
255151314007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21000, while the sum is 34.
Adding to 255151314007 its reverse (700413151552), we get a palindrome (955564465559).
The spelling of 255151314007 in words is "two hundred fifty-five billion, one hundred fifty-one million, three hundred fourteen thousand, seven".
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