Base | Representation |
---|---|
bin | 1110110110100000110… |
… | …1000001010010000101 |
3 | 220101120221012201112122 |
4 | 3231220031001102011 |
5 | 13140022214022203 |
6 | 313114230055325 |
7 | 24301613246036 |
oct | 3555015012205 |
9 | 811527181478 |
10 | 255151314053 |
11 | 992332a0799 |
12 | 415497aa545 |
13 | 1b0a338980c |
14 | c4c6a20a8d |
15 | 69851ae538 |
hex | 3b68341485 |
255151314053 has 2 divisors, whose sum is σ = 255151314054. Its totient is φ = 255151314052.
The previous prime is 255151314007. The next prime is 255151314071. The reversal of 255151314053 is 350413151552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 223631572609 + 31519741444 = 472897^2 + 177538^2 .
It is a cyclic number.
It is not a de Polignac number, because 255151314053 - 234 = 237971444869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255151314553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127575657026 + 127575657027.
It is an arithmetic number, because the mean of its divisors is an integer number (127575657027).
Almost surely, 2255151314053 is an apocalyptic number.
It is an amenable number.
255151314053 is a deficient number, since it is larger than the sum of its proper divisors (1).
255151314053 is an equidigital number, since it uses as much as digits as its factorization.
255151314053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 255151314053 in words is "two hundred fifty-five billion, one hundred fifty-one million, three hundred fourteen thousand, fifty-three".
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